next up previous
Next: Using factorization backwards Up: Factoring and division of Previous: The remainder, factor, and

Common factorization situations

It is quite valuable to know how to factor differences of powers and (when possible) sums of powers:

\begin{displaymath}(a^n-b^n)=(a-b)(a^{n-1}+a^{n-2}b+ a^{n-3}b^2 + \ldots + b^{n-1}\end{displaymath}

With the familiar cases

\begin{displaymath}(a^2-b^2)=(a-b)(a+b)\end{displaymath}

and

\begin{displaymath}(a^3-b^3)=(a-b)(a^2+ab+b^2).\end{displaymath}

For odd powers we also can factor the sum:

\begin{displaymath}(a^3+b^3)=(a+b)(a^2-ab+b^2)\end{displaymath}


\begin{displaymath}(a^5+b^5)=(a+b)(a^4-a^3b+a^2b^2-ab^3+b^4)\end{displaymath}

A quadratic $x^2+ax +b$ which is factorable into $(x+r_1)(x+r_2)$ will have $r_1r_2=b$ and $r_1+r_2=a$.


Larry Stout 2003-01-09