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Handling exponents

Exponents behave nicely with respect to multiplication and division.

\begin{eqnarray*}(ab)^n&=&a^nb^n\ a^na^m&=&a^{n+m}\ \left(a^n\right)^m &=& a^{nm} \\
\left(\frac{a}{b}\right)^n&=& a^n b^{-n}\end{eqnarray*}



They do not behave nicely with respect to addition:

\begin{displaymath}(a+b)^n\neq a^n+b^n\end{displaymath}

unless, of course, $n=1$.

Properties of logarithms follow from the properties of exponentials once we define

\begin{displaymath}a^x=y \Leftrightarrow x = \log_a( y)\end{displaymath}

The equations above then tell us that

\begin{eqnarray*}\log_a(nm)&=&\log_a(n)+\log_a(m) \ \log_a(n^m)&=& m\log_a(n)\end{eqnarray*}



The rule

\begin{displaymath}(a^n)^m=a^{nm}\end{displaymath}

tells us that

\begin{displaymath}\left(a^{\frac1n}\right)^n=a\end{displaymath}

so

\begin{displaymath}\sqrt[n]{a} = a^{\frac1n}\end{displaymath}

So for instance

\begin{eqnarray*}\sqrt{x} &=& x^{\frac12} \\
\sqrt[3]{x} &=& x^{\frac13}\\
\sqrt[3]{x^2} &=& x^{\frac23} \end{eqnarray*}





Larry Stout 2003-01-09