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Induction Proofs

The following all follow from the third axiom in the definition of \ensuremath{\mathbb{N}} and are equivalent:
  1. Mathematical Induction: If a property $\Phi(x)$ holds for $x=0$ and if the implication $\Phi(n)\rightarrow \Phi(n+1)$ holds, then $\Phi(x)$ holds for all $x\in \ensuremath{\mathbb{N}}$.
  2. Strong induction: If a property $\Phi(x)$ holds for $x=0$ and if the implication $(\forall_{k<n}\Phi(k))\rightarrow \Phi(n)$ holds, then $\Phi(x)$ holds for all $x\in \ensuremath{\mathbb{N}}$.
  3. Well ordering of \ensuremath{\mathbb{N}}: Any non-empty subset $S\subseteq \ensuremath{\mathbb{N}}$ has a least element.

If a mathematician uses ``...'' in the middle of an informal argument, it is a good bet that there is an induction argument called for in a more formal proof.

The following examples use one of these three proof techniques:

Proposition 93   Given that $\displaystyle{\frac{d}{dx} x =1}$, $\displaystyle{\frac{d}{dx} 1 =0}$, and the product rule

\begin{displaymath}\frac{d}{dx} u v = u \frac{d}{dx} v + v \frac{d}{dx} u\end{displaymath}

we get $\displaystyle{\frac{d}{dx}x^n=nx^{n-1}}$ for all $n\in \ensuremath{\mathbb{N}}$.

(4 Points )

Proposition 94   The product of n numbers may be grouped any way you please.

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Proposition 95   $\displaystyle{\sum_{k=0}^n k = \frac{n(n+1)}{2}}$.

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Proposition 96   $\displaystyle{\sum_{k=0}^n k^2 = \frac{n(n+1)(2n+1)}{6}}$.

(4 Points )

Proposition 97   $\displaystyle{\sum_{k=0}^n k^3 = \left(\frac{n(n+1)}{2}\right)^2}$.

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Proposition 98   $\displaystyle{\sum_{k=0}^n a^k = \frac{1-a^{k+1}}{1-a}}$.

(4 Points )

Proposition 99   Every natural number $n>1$ is either a prime or is the product of primes.

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Theorem 100 (Division Algorithm)   If $m$ and $n$ are positive natural numbers, then there are natural numbers $q$ and $r$ with $0\leq r < m$ and $n=qm+r$.

(4 Points )

Theorem 101 (Euclidean Algorithm)   If $m$ and $n$ are positive natural numbers, then the greatest common divisor of $m$ and $n$ can be expressed as $an+bm$ for some integers $a$ and $b$.

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Corollary 102   If $n\vert pq$ and the largest common divisor of $n$ and $p$ is 1, then $n\vert q$.

(2 Points )

Corollary 103   Any natural number $n>1$ has a prime factorization which is unique up to the order of the factors.

(4 Points )
next up previous
Next: Integers: Extending a system Up: Numbers Previous: Basic Divisibility Theory
Larry Stout 2001-08-17