Take f[x] = Sin[1/x]. Make several plots of f[x] to see what happens as
x -> 0. Does [Graphics:LimitsBasicsgr103.gif] f[x] exist? Explain why or why not.

Answer:

Clear[f];
f[x_]= Sin[1/x]
[Graphics:LimitsBasicsgr2.gif][Graphics:LimitsBasicsgr104.gif]

Here are the plots zooming in on what happens as x-> 0:

Plot[f[x],{x,-10,10},PlotRange->{-1,1}]
[Graphics:LimitsBasicsgr2.gif][Graphics:LimitsBasicsgr105.gif]
[Graphics:LimitsBasicsgr2.gif][Graphics:LimitsBasicsgr106.gif]

Plot[f[x],{x,-1,1},PlotRange->{-1,1}]
[Graphics:LimitsBasicsgr2.gif][Graphics:LimitsBasicsgr107.gif]
[Graphics:LimitsBasicsgr2.gif][Graphics:LimitsBasicsgr108.gif]

Plot[f[x],{x,-.1,.1},PlotRange->{-1,1}]
[Graphics:LimitsBasicsgr2.gif][Graphics:LimitsBasicsgr109.gif]
[Graphics:LimitsBasicsgr2.gif][Graphics:LimitsBasicsgr110.gif]

Plot[f[x],{x,-.001,.001},PlotRange->{-1,1}]
[Graphics:LimitsBasicsgr2.gif][Graphics:LimitsBasicsgr111.gif]
[Graphics:LimitsBasicsgr2.gif][Graphics:LimitsBasicsgr112.gif]

Certainly not nice behavior! As x gets closer and closer to 0, the values of f[x] still range all the way from -1 to +1. The graph does not seem to be settling down and approaching a single point as x->0. Since there is no trend in the y-values, we have no hope that [Graphics:LimitsBasicsgr113.gif] f[x] exists.